For an integer N find the number of trailing zeroes in N!.
#include <stdio.h>
#include <conio.h>
void main(){
int n, i, count=0, sum = 1;
printf("enter the number: ");
scanf("%d", &n);
for(i=n; i>=1; i--)
sum = sum*(i);
{
int count_digit(int sum){
{
if(sum > 0)
{
if(sum%10==0)
count++;
count_digit(sum/10);
}
return count;
}
}
printf("%d", count_digit(sum));
}}
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Tags
Coding